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# Vertical projectile motion problems with solutions

### Projectile motion - problems and solutions Solved

• Projectile motion - problems and solutions. 1. A bullet fired at an angle θ = 60o with a velocity of 20 m/s. Acceleration due to gravity is 10 m/s2. What is the time interval to reach the maximum height? Known : The initial velocity of bullet (vo) = 20 m/s
• Projectile Motion: Solving Problems With Angles Ch. 5 in your text book Students will be able to: 1) Calculate the horizontal and vertical velocity components of a velocity vector 2) Solve projectile motion problems involving angle
• Practice Problems - PROJECTILE MOTION Problem 1: A shotput is thrown. For the each of the indicated positions of the shotput along its trajectory, draw and label the following vectors: the x-component of the velocity, the y-component of the velocity, and the acceleration. Explain why you drew the vectors as you did
• Problem 8. The trajectory of a projectile launched from ground is given by the equation y = -0.025 x2 + 0.5 x, where x and y are the coordinate of the projectile on a rectangular system of axes. a) Find the initial velocity and the angle at which the projectile is launched. Solution to Problem 8
• Projectile Motion: Practice Problems & Solutions. From here we need to use the initial vertical velocity to find the time it takes the car to reach the top of its path and fall to the ground. Let's think about this in two parts; the time it takes to reach hMAX first: tTOP = 42.43/10 = 4.243 s
• Refer to the projectile motion page. To find maximum height set v1y = vo sin θ. We know that at maximum height there is zero vertical velocity (v2y = 0). There is a specific equation on the projectile motion page which you can use to solve for the maximum height when v2y = 0
• Projectile motion numerical problems class 11 Solution: Here we have to find out the value of vertical displacement y when horizontal displacement is x = 10 m. If the value of y comes out to be less than the height of the wall then the projectile hits the wall otherwise not
• TOPIC 1.4: PROJECTILE MOTION S4P-1-15 Solve simple free-fall problems using the special equations for constant acceleration. Include: horizontal and vertical components of motion of the curved path of a projectile (without air resistance) S4P-1-16 Draw free-body diagrams for a projectile at various points along its path (with and without air.

Mechanics: Vertical projectile motion Grade 12 FSDoE Revision 2013 Page 7 of 10 5.4 One second (1 s) after projectile X is fired, the man's friend fires a second projectile Y upwards at a velocity of 49 m·s-1 FROM THE GROUND BELOW THE CLIFF. The first projectile, X, passes projectile Y 5,23 s after. The key to solving this type of problem is knowing that the vertical component of motion is the same as what happens in example 1 above, when the body is dropped from a height. So as the projectile is moving forwards, it is also moving downwards, accelerated by gravity. Time of flight. t = √(2h/g) as calculated in example Plug n' Chug: Step 1: Calculate the time required for the car to freefall from a height of 72 m. but since , the equation simplifies to rearranging for the unknown variable, , yields. Step 2: Solve for initial velocity: The answer is 5.80 m/s Learn how to use the Vertical Motion Model in this free math video tutorial by Mario's Math Tutoring. We look at how long it takes for a ball thrown up in t.. Projectile motion - beginners. 245 m. 245 \text { m}. 245 m. What is the magnitude of the body's vertical velocity when it strikes the ground? g = 10 m/s 2. g = 10 \text { m/s}^2. g = 10 m/s2. 30 ^\circ 30∘ angle with the horizon

### Projectile Problems with Solutions and Explanation

3.13. IDENTIFY:!The car moves in projectile motion. The car travels downward during the time it travels 61.0 m horizontally. SET UP:!Take to be downward. , . , . EXECUTE:!Use the vertical motion to find the time in the air: gives Then gives . (b) since . . . EVALUATE:!We calculate the final velocity by calculating its x and y components. ' 3.56 PROJECTILE MOTION PRACTICE QUESTIONS (WITH ANSWERS) * challenge questions Q1. A golfer practising on a range with an elevated tee 4.9 m above the fairway is able to strike a ball so that it leaves the club with a horizontal velocity of 20 m s-1. (Assume the acceleration due to gravity is 9.80 m s-2, and the effects of air resistance may b Projectile Motion Questions and Answers Test your understanding with practice problems and step-by-step solutions. Browse through all study tools Kinematics Exam3 and Problem Solutions 1. As you can see from the given picture, ball is thrown horizontally with an initial velocity. Find the time of motion. (g=10m/s2) Ball does projectile motion in other words it does free fall in vertical and linear motion in horizontal. Time of motion for horizontal and vertical is same. Thus in vertical; h=1/2g. t2 80=1/2

### Projectile Motion Practice & Solutions SchoolWorkHelpe

1. e the position, velocity and displacement of a projectile at any given time
2. Introducing the Toolbox method of solving projectile motion problems! Here we use kinematic equations and modify with initial conditions to generate a too..
3. The motion of a projectile can be studied by splitting it into two components: horizontal motion and vertical motion. Assume the projectile starts from a point O. Using horizontal and vertical axes through O allows the position of the projectile at any point in its motion to be given in terms of two coordinates (x, y). The velocity of the.
4. Solution: Concepts: Kinematics, projectile motion; Reasoning: The rock is a projectile. For projectile motion we have x = v cosθ t, y = v sinθ t - ½gt 2. Details of the calculation: (a) The distance between the rock and the launch point is D = (x 2 + y 2) ½ = (v 2 t 2 + g 2 t 4 /4 - vgt 3 sinθ) ½. For 0 < θ < 90 o and v > 0 the distance.
5. 3.2 Vertical projectile motion (ESCJW) In Grade 11, we studied the motion of objects in free fall and saw that such an object has a constant gravitational acceleration of \ (\vec {g}\). We now study the motion of objects that are moving upwards or downwards while experiencing a force due to gravity. We call this projectile motion

A non-horizontally launched projectile is a projectile that begins its motion with an initial velocity that is both horizontal and vertical. To treat such problems, the same principles that were discussed earlier in Lesson 2 will have to be combined with the kinematic equations for projectile motion While you are jumping, you are a projectile. We solve projectile motion problems by considering the xand y components separately, keeping in mind that the time in air is common. We write out the i and jinformation in separate columns including the information that we can infer or that we are supposed toknow like the fact that running horizontally implies that voy = 0. A projectile is fired from ground level with velocity 500m/s at 30 degree to the horizontal.Find it's horizontal range,the greatest vertical height to which it rises,and the time to reach the greatest height.what is the least speed with which it could be projected in order to achieve the same hirihorizo range?(Neglect air resistance to the motion

Projectile motion will be analysed using the equations of motion introduced in Year 11 - Module 1: Kinematics. However, projectile motion is two dimensional motion. - For the purpose of our study, we must break up the two-dimensional motion into two one-dimensional motions. - The horizontal motion (along T) and vertical motion (along. 8. The vertical motion of a projected object is independent of its horizontal motion. 9. A projectile moves horizontally with constant velocity while being accelerated vertically. The result is a motion in a curved path. 10. The path of a projectile is called its trajectory. The trajectory of a projectile in free fall is a parabola Acceleration in the horizontal projectile motion and vertical projectile motion of a particle: When a particle is projected in the air with some speed, the only force acting on it during its time in the air is the acceleration due to gravity (g). This acceleration acts vertically downward Accelerations in the horizontal projectile motion and vertical projectile motion of a particle: When a particle is projected in the air with some speed, the only force acting on it during its time in the air is the acceleration due to gravity (g). This acceleration acts vertically downward. Projectile Motion - Definition & Formula | Projectile. Motion Projectile Problems (MPP) 30102016 ©L m2a0H1F6Y eKguitfaW ySVojfotKw\aYrbe] aLyL[CY.q Z fAdlWlo croiqgQhetssA xrpeZsmeravIeadM.-1-1) Erika jumped off a cliff into the ocean in Acapulco while vacationing with some friends. Her height as a function of time could be modeled by the function h (t) = -16t2 + 16t + 96 where t is the time i

the simple projectile motion problems and solutions examples is universally compatible considering any devices to read. Accelerations in the horizontal projectile motion and vertical projectile motion of a particle: When a particle is projected in the air with some speed, the only force acting on it during its time in the air. Read PDF Simple Projectile Motion Problems And Solutions Examples Simple Projectile Motion Problems And Solutions Examples As recognized, adventure as with ease as experience not quite lesson, amusement, as capably as covenant can be gotten by just checking out a ebook simple projectile motion problems and solutions examples afterward it is not directly done, you could give a positive response. Topic 2 Vertical projectile motion in one dimension (1D) The Solutions for all Physical Sciences Grade 12 Learner's Book, • knowledge and skills in scientific inquiry and problem solving; • the construction and application of scientific and technological knowledge This projectile motion problem involves initially horizontal projectile motion, which means there is no initial vertical velocity component to consider. Answer: h = 0, Δdx = 10.102 m. Hint and answer for Problem # 7. You need to solve this with numerical methods which accounts for the effects of air resistance

projectile-motion-practice-problems-with-answers 1/1 Downloaded from www.iitiim.com on August 1, 2021 by guest Read Online Projectile Motion Practice Problems With Answers Recognizing the showing off ways to get this ebook projectile motion practice problems with answers is additionally useful Sections: Projectile motion, General word problems, Max/min problems. For our purposes, a projectile is any object that is thrown, shot, or dropped. Usually the object is moving straight up or straight down. An object is launched at 19.6 meters per second (m/s) from a 58.8-meter tall platform. The equation for the object's height s at time t.

Solution t v v v v at d v t at v v ad d i f f i i f i 2 2 2 1 2 Using what we know from the problem, we can eliminate the third and fourth equations of motion. Since we know initial and final velocities, we can use equation 1, eliminating the need to use a quadratic. Substituting v i and v f into equation 1 gives vsinT vsinT g Vertical Projectile Motion. Vertical Projectile Motion - Displaying top 8 worksheets found for this concept.. Some of the worksheets for this concept are Vertical projectile motion and momentum, Projectile practice work, Projectile motion, Projectile motion solving problems with angles, Projectile review work with answers, Physical sciences grade 11 term 2 content booklet, Physical sciences. Projectile motion is the motion of an object through the air that is subject only to the acceleration of gravity. To solve projectile motion problems, perform the following steps: 1. Determine a coordinate system. Then, resolve the position and/or velocity of the object in the horizontal and vertical components Circular Motion Problems - ANSWERS 1. An 8.0 g cork is swung in a horizontal circle with a radius of 35 cm. It makes 30 revolutions in 12 seconds. What is the tension in the string? (Assume the string is nearly horizontal) T=time/revolutions=0.4 s Period is the time per revolution F=ma Write down N2L F tension = m 1 Range of Projectile Motion When the projectile comes back to the ground, the vertical displacement is zero, thus we have 0 = v 0 sin t 1 2 gt2 Solving for t, we have t= 0; 2v 0 sin g 1. The rst solution gives the time when the projectile is thrown and the second one is the time when it hits the ground. Plugging in the second solution int Worksheet: Have students solve the problems on the Projectile Motion Problem Worksheet. Once they are finished, review the solutions as a class. This is a good indicator of whether students grasp the mathematical concepts behind projectile motion

The solution of this problem begins by equating the known or given values with the symbols of the kinematic equations - x, y, v ix, v iy, a x, a y, and t. Because horizontal and vertical information is used separately, it is a wise idea to organized the given information in two columns - one column for horizontal information and one column for vertical information You should have/know a general statement of position of a particle from initial location, initial velocity and initial acceleration/sum of forces. Just plug in what you know from the statement of the problem and solve for what you need. Of course,.. If you are looking for a place to get accurate projectile motion answers, the search is over. Help with Vertical Projectile Homework Questions. Though projectile motion combines both the vertical and horizontal motions, you can analyze them separately. As earlier mentioned, vertical projectile motion entails moving along the y-axis Projectile motion is the motion of an object subject only to the acceleration of gravity, where the acceleration is constant, as near the surface of Earth. To solve projectile motion problems, we analyze the motion of the projectile in the horizontal and vertical directions using the one-dimensional kinematic equations for x and y Projectile Motion. Projectile Motion - Displaying top 8 worksheets found for this concept.. Some of the worksheets for this concept are Ideal projectile motion, Midland independent school district overview, Physics 11 projectile motion work, Physics work lesson 6 projectile motion, Projectile motion practice, Projectile motion, Projectile motion solving problems with angles, Projectile.

### Projectile Motion Problems - Real World Physics Problem

In this lesson we practice using the equations of motion to solve projectile motion problems. 5. Graphing Free Fall I In this lesson we draw position-time, velocity-time and acceleration-time graphs for projectile motion. 6. Graphing Free Fall II We've drawn graphs for a projectile moving downward This equation computes the vertical distance from an origin of an object at time (t) based on its initial position from the origin (Y_o), it's initial velocity (V_yo) and a constant deceleration (g) due to gravity. y = y_0 + v_y0*t - 0.5*g*t^2` APPLICATIONS This is the typical equation for an object launched vertically against gravity, neglecting any forces other than gravity Detailed solution to problem #9 We will begin by substituting our givens in to the projectile height formula: At time t = 0, vo = 96 ft/sec, and so = 200 feet. The graph of the equation depicting the path of the ball is as follows: We want to know what the value of t will be when = 300. To find out, we substitute 300 for PROJECTILE MOTION WORKSHEET A ball is kicked horizontally at 8.0 m/s from a cliff 80m high. How far from the base of the cliff will the stone strike the ground? How long will it take a shell fired from a cliff at an initial velocity of 800 m/s at an angle 300 below the horizontal to reach the ground 150m below

The motion of an object thrown or projected into the air, subject only to the acceleration of gravity, is referred to as projectile motion. The object is known as a projectile, and its path is known as its trajectory. Falling object motion, as described in Problem-Solving Basics for One-Dimensional Kinematics, is a simple one-dimensional type. Projectile Motion Problems, Worksheet 1: Use the kinematic equations that we've been using, but now apply them in horizontal direction the problem becomes a constant velocity problem. Usually this is the only equation you will Example Problem 1 Solution: Given Information: • vertical distance,. • initial vertical velocity,. the motion of. Numerical Problems on Rolling motion, Torque, and Physics numerical problems worksheet on centripetal IGCSE physics force and motion worksheet with Projectile Motion Numerical problems with solution 101 Solved Numerical Problems in Physics class 9 Motion graphs of vertical fall against air-drag

### Projectile Motion Numerical problems word problem

1. Projectile Motion Without Initial Velocity. In the simplest kind of projectile motion problems, there is no initial velocity. An object is simply dropped so that the Earth's magnetic field pulls it toward the ground at a rate of 9.81 m/s 2.This acceleration is all in a vertical direction (i.e. toward the Earth's surface).Gravity doesn't have a horizontal component, and so (unlike the.
2. Problem # Projectile motion all questions solutions of M Karim..!! For the Love of Physics (Walter Lewin's Last Lecture) Projectile Motion Projectile launched off a cliff at an angle Projectile Motion Example - How fast when it hits the ground Projectile Motion: Problem Solving Vertical Projectile Motion
3. e how long it takes the rock to hit the ground. y - yo = vot + ½at2. -6 - 0 = 0 + ½ (-9.8)t2. t = 1.1 s. b. (easy) Deter
4. PROJECTILE MOTION 1. PROJECTILE MOTION by: JANET BRIGIDA A. CATIPON MHS Science 9 Teacher 2. LEARNING OBJECTIVES • Define Projectile Motion • Explain Projectile Motion • Identify the types of Projectile Motion • Differentiate the types of Projectile Motion • Explain and summarize all the kinematics equation in solving Projectile Motion problems • Solve problems involving the types.

### How to Solve Projectile Motion Problems: Applying Newton's

1. ed completely by the vertical motion. Thus, any projectile that has an initial vertical velocity of 21.2 m/s and lands 10.0 m below its starting altitude spends 3.79 s in the air. (b) We can find the final horizontal and vertical velocities v x v x and v y v y with the use of the result from (a)
2. MOTION OF A PROJECTILE (Section 12.6) Projectile motion can be treated as two rectilinear motions, one in the horizontal direction experiencing zero acceleration and the other in the vertical direction experiencing constant acceleration (i.e., gravity). For illustration, consider the two balls on the left. The red ball falls from rest, whereas th
3. This question is a little vague. But I'd say that in general, you can think of the horizontal and vertical components of projectile motion independently, and as separate one-dimensional problems. If a projectile is being launched from the ground o..
4. oral, and graphical solutions to design problems. Engineering-science, which deals with the study of relative motion between the various parts of a machine, and forces which act on (curvilinear or rectilinear) paths. • Complex motion: a simultaneous combination of The path of such a particle is called a projectile and the motion is called.
5. e the acceleration of free fall experimentally. Analyse projectile motion, include the resolution of vertical and horizontal components of acceleration, velocity and displacement. Qualitatively describe the effect of fluid resistance on falling objects or projectiles, including reaching ter

### Projectile Motion Problem Solving ( Read ) Physics CK

1. Vertical projectile motion | Vertical projectile motion in You will find a book like this useful as a reference and for completing additional practice problems to enhance your learning of the material. ----- The copyright of all content and materials in this course are owned by either the Georgia Tech Research Corporation or Dr. Wayne Whiteman
2. Parabolic motion, work and kinetic energy, linear momentum, linear and angular motion - problems and solutions. 1. A ball is thrown from the top of a building with an initial speed of 8 m/s at an angle of... Transverse waves - problems and solutions. 1. The distance between the two troughs of the water surface waves is 20 m
3. Figure 5.29 (a) We analyze two-dimensional projectile motion by breaking it into two independent one-dimensional motions along the vertical and horizontal axes. (b) The horizontal motion is simple, because a x = 0 a x = 0 and v x v x is thus constant. (c) The velocity in the vertical direction begins to decrease as the object rises; at its highest point, the vertical velocity is zero
4. Type 1 projectile motion. Projectile practice worksheet ans. 12 best projectile motion questions and answers q a. Projectile motion answer key projectile motion has two components horizontal x and vertical y as can be seen below. An arrow is fired directly horizontal off a cliff that is 10 0 meters tall with a

### Vertical Motion Math Problem (Formula) - YouTub

1. The projectile follows a parabola because gravity affects the two components of horizontal and vertical motion. The horizontal component is not affected by gravity. However, the vertical part is constantly affected by gravity, so its height increases first, then decreases and accelerates under the influence of gravity
2. Problems with detailed solutions. How far from the base of the cliff will the stone strike the ground. Some of the worksheets displayed are practice problems of horizontal andor vertical projectile show your projectile motion work ideal projectile motion physics work lesson 6 projectile motion projectile motion and quadratic functions read from.
3. d. First, the projectile's horizontal velocity must remain constant, since gravity is only acting in the vertical direction.
4. Projectile motion worksheet 1 answer key. Your resultants will be the diagonals of the rectangles draw from the tail to tail vectors to the opposite corner of the rectangle always. Unit 5 worksheets projectile motion projectile practice and drawing problem. Key to solve projectile problems you must divide up your information into two parts
5. physics-projectile-motion-problems-and-solutions 2/2 Downloaded from cermes.coe.fsu.edu on August 5, 2021 by guest bulletproof analysis Burnett's future career interest is the following: plasma physics motion; for example, trains that hover above their tracks. But trains are really heavy, and weight becomes a problem whe
6. Problem 5 Solution Problem 6: A brick is thrown upward from the top of a building at an angle of 25 degrees above the horizontal and with an initial speed of 15 m/s. If the brick is in the air for 3 seconds, how high is the building? (Draw a picture.) Problem 6 Solution Problem 7: A daredevil tries to jump a canyon of width 10 m. To do so, he.

### Projectile motion - beginners Practice Problems Online

Vertical motion is any type of upwards or downwards motion that is constant. In a vertical motion problem, you may be asked about instantaneous velocity, and/or average velocity. To solve for instantaneous velocity we will need to take the derivative of our position function The formulas for vertical motion that have time in them are y = y o ±v yo t ½gt2 and v yf = ±v yo gt. The first one is for height and the second one for final velocity. We will use the formula for height and modify it for our situation. The freshman has no initial vertical velocity (he has horizontal velocity but not vertical velocity) Download [174.68 KB] Projectile Motion Presentation : Contents - What is Projectile Motion?, Types of Projectile Motion, Examples of Projectile Motion, Factors Affecting Projectile Motion and exercises with solutions. Download [700.00 KB] If you found these worksheets useful, please check out Law of Conservation of Momentum Worksheet Answers. Ignoring air resistance, the vertical velocity of a projectile changes because it is subject to constant gravitational acceleration. The vertical position of a projectile changes nonlinearly with time, because it has changing vertical velocity. Ig..

Steps to Solve a Projectile Motion Problem: Draw a vector diagram. Find the horizontal and vertical components of velocity. Solve for each component (horizontal or vertical) separately. Remember for acceleration: horizontal = 0 and vertical = -9.8 m/s2. ROT: find time first (using vertical components) Ignore air resistance. Check for units and. Projectile A: Firing angle = 30°, initial speed = 40 m/s. Projectile B: Firing angle = 45°, initial speed = 40 m/s. Projectile C: Firing angle = 15°, initial speed = 40 m/s. Projectile D: Firing angle = 60°, initial speed = 40 m/s. 3. (moderate) A cannonball (placed on a wall 20 m above the ground) is shot at 20° firing angle with a. To solve projectile problems, you must divide up your information into two parts: _____ which has _____ motion and _____ which has _____ motion. What equations will you use for each type of motion? 1. A ball rolls off a 1.0 m high table and lands on the floor, 3.0 m away from the What is the vertical velocity of the ball just before it hits. Projectile Problems 1. To solve projectile problems, you must divide up your information into two parts: _____ distance which has _____ motion and _____ distance which has _____ motion. 2. What equations will you use for each type of motion? 3. A ball rolls off a 1.0 m high table and lands on th

### Projectile Motion Questions and Answers Study

Vertical Projectile Motion Problem Thread starter TheRedDevil18; Start date May 11, 2013; May 11, 2013 #1 TheRedDevil18. 408 1. equations of motion The Attempt at a Solution 1.1) Okay, I worked out the total time to go up and got 3's and then doubled it for coming down and got 6's. Projectile Intro Problems 1. (review) A safe is dropped from the top of a building 125 meters high. a. What is its initial vertical velocity? Horizontal velocity? b. How far does it fall in the first second? The second second? c. How long does it take to hit the ground? d. What is its vertical speed after 2 seconds? 4 seconds? e negative. 2 The vertical motion is described by Y = 1 2 g t as before but now after substitution (-15 m)= 1 2 I-9.8 mës2M t2 so the two minus signs cancel and solving we get t = 1.75 s the same as before. The motion in the x-direction X = V x t is not effected by the y axis so everything is unchanged in the x direction. | 5. Projectile Motion. The answers to each problem follow it in parentheses. They also link to a solution to the problem. Try the problem, check your answer, and go to the solution if you do not understand. 1. Brian's car, the Quantum, leaves the ground with an initial vertical velocity of 53 m/s and a horizontal velocity of 42 m/s

### Kinematics Exam3 and Problem Solution

SOLUTION Ex 5; Exercise 6. The path of a projectile is given below. Sketch the position, velocity and acceleration vectors for the projectile in the position shown and write the components of acceleration. SOLUTION Ex 6; Exercise 7. Jack, standing on a cliff, throws a rock into a lake 20 m below with initial velocity 25 m/s at 53° above. projectile motion, what are the features of the motion? (1) _____ Horizontally Launched Projectile Problems 10 A ball projected horizontally with an initial velocity of 20. m/s east, off a cliff 100. meters high. [Neglect air is the vertical component of the projectile's velocity Projectile Motion Vertical Motion. Displaying top 8 worksheets found for - Projectile Motion Vertical Motion. Some of the worksheets for this concept are Projectile motion work solutions odds, Physics work lesson 6 projectile motion, Projectile motion solving problems with angles, Projectile review work with answers, Physical sciences grade 11 term 2 content booklet, Physical sciences grade 12. In the projectile motion , if air resistance is ignored , the horizontal motion is at. A. constant acceleration. B. variable acceleration. C. constant velocity. D. constant retardation. View Answer. Two projectiles of same mass and with samevelocity are thrown at an angle 60 & 30 withthe horizontal, then which quantity will remainsame : A       Projectile Motion Applications. Again, parametric equations are very useful for projectile motion applications. With parametric equations and projectile motion, think of $$x$$ as the distance along the ground from the starting point, $$y$$ as the distance from the ground up to the sky, and $$t$$ as the time for a certain $$x$$ value and \(y. Combining these two influences upon the vertical displacement yields the following equation. y = viy • t + 0.5 • g • t2. (equation for vertical displacement for an angled-launched projectile) where viy is the initial vertical velocity in m/s, t is the time in seconds, and g = -9.8 m/s/s (an approximate value of the acceleration of gravity) While solving problems in projectile motion, I expect students to solve these problems by drawing a vertical line on their paper and write Vertical Motion on the first column and Horizontal Motion on the second column because in projectile motion, the Vertical Motion is INDEPENDENT of the Horizontal Motion a) The equation you need to find the vertical distance is: . You are already given u, a and t. And oh hey. Since u = 0, you can simplifyy the formula and make your life a little easier. The formula is simplified to: . Now, let's solve. b) To find the initial horizontal velocity, you use the same formula that you used to find the vertical distance Projectile motion is the combination of horizontal and vertical motion. The speed of the horizontal motion remains the same but it changes in vertical motion. So vx = vix v x = v i x where vx v x is the horizontal velocity (the subscript x x reminds the velocity along x-axis). The acceleration in vertical motion is −g − g -Explore why we analyze the motion of a projectile separately in the horizontal and vertical directions.-Analyze the horizontal and vertical components of motion separately by doing an example.-Reinforce the idea that elapsed time is the same for an object at its given position in the vertical direction and the horizontal direction